SOLUTION: cos(2x-pi/6) = sqrt3/2 solve the equation on the interval [0,2pi).

Algebra.Com
Question 1051496: cos(2x-pi/6) = sqrt3/2
solve the equation on the interval [0,2pi).

Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
Where the cosine is equal to sqrt(3)/2 is at pi/6 and 11pi/6.
Set 2x-pi/6=pi/6.
2x=2pi/6
x=pi/6
---------------
Set 2x-pi/6=11pi/6
2x=12pi/6
x=pi-----(6pi/6)

RELATED QUESTIONS

Solve the equation on the interval 0 < theta < 2pi cot 2theta/3 =... (answered by lwsshak3)
solve the equation, [0, 2pi) a)... (answered by lwsshak3)
Solve each equation on the interval 0 (answered by lwsshak3)
Solve the following equation on the interval [0, 2pi] cos^2 x + 2 cos x + 1 =... (answered by josgarithmetic)
Please solve the equation for the interval [ 0, 2pi ]: {{{2cos^2(2x)-cos(2x)=0}}}... (answered by ikleyn)
Solve on the interval [0, 2pi] Sin*2x - sin x + 1=... (answered by lwsshak3)
Solve the equation on the interval 0 < theta < 2pi cos^2 theta-sin^2 theta+sin... (answered by tarungehlot)
Find all solutions of each of the equations in the interval (0, 2pi) cos(x- pi/2) +... (answered by lwsshak3)
solve the equation on the interval [0,2pi] cos(20)=... (answered by Fombitz)