Question 1047332: Please find the minimum and maximum values of the expression . Found 3 solutions by josmiceli, robertb, ikleyn:Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website! The maximum of both sin and cos function is
So the maximum of the expression is
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The even exponents make any negative value positive,
so the minimum has to be
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website! Well, I am sending this commentary to "ikleyn"--
Of course, it will be "SLIGHTLY SHIFTED".
One MISTAKE you made was that you plotted as if x was the independent variable in the function, and over the SAME COORDINATE SYSTEM! It was NOT.
Remember, I let .
So naturally, the lowest points of the two graphs will NOT jive. BUT, what is guaranteed is that they will have the SAME LOWEST level.
Another MISTAKE you made was that, z is a composite function, and as such, its domain, as a function of w, is only . Meaning, your green-colored graph is WRONG.
The range of z is [,1], or[0.05310578625,1] (approximately).
In fact, I can even predict/estimate the amount of "shift" that you're talking about:
.
=
=
Now let . ===> , and
===> .
Let .
===> . Letting this equal to zero, we get
.
===> , after taking cube root of both sides.
===> .
===>
= , since .
≈ 0.5860760201.
Now to the left of 0.5860760201, z' < 0, so z is decreasing on [0, 0.5860760201).
To the right of 0.5860760201, z' > 0, so z is increasing on (0.5860760201,1].
Hence there is a local minimum at w = 0.5860760201.
We only need to check the other critical points where the derivative doesn't exist, namely at w = 0 and w = 1,
to determine the other possible extrema.
At w = 0, z = 1.
At w = 1, z = 1.
Therefore the maximum of is , while the minimum is
, approximately.