SOLUTION: what is the minimum value of 2sin^2(x)+3cos^2(x)
Algebra.Com
Question 1046264: what is the minimum value of 2sin^2(x)+3cos^2(x)
Answer by ikleyn(52835) (Show Source): You can put this solution on YOUR website!
.
what is the minimum value of 2sin^2(x)+3cos^2(x)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
2sin^2(x)+3cos^2(x) = ( 2sin^2(x)+2cos^2(x) ) + cos^2(x) = 1 + cos^2(x).
The minimum value is 1. It is achieved when cos(x) = 0, i.e. at x = , where k is any integer.
RELATED QUESTIONS
What is the maximum and minimum value value of y=2sin(x)+2 and what are the corresponding (answered by stanbon)
What is the period of y=1/3cos... (answered by MathLover1)
Solve the equation graphically:
-cos^3 x + 3cos^2 x = 2sin x =... (answered by stanbon)
Determine how many solutions there are for the equation:
2sin x + 3cos x= 2 (answered by Edwin McCravy)
What is the minimum value of... (answered by josgarithmetic,josmiceli)
3cos (x+30°)/2 + 2sin^2 (x+30°)/2 = 3
find x?
(answered by lwsshak3)
What is the minimum of... (answered by Alan3354)
If sin(x) + sin^2(x) = 1, then the value of cos^12(x) + 3cos^10(x) + 3cos^8(x) + cos^6(x) (answered by ikleyn,Edwin McCravy,AnlytcPhil)
What is the maximum value of the transformed function: g(x)=−3cos[2(x−60°)]+3?
-6
(answered by ikleyn,greenestamps)