SOLUTION: Please help. I would like the answer in radians. Thanks! 2cos^2x + sinx -1 =0

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Question 1045455: Please help. I would like the answer in radians. Thanks!
2cos^2x + sinx -1 =0

Found 3 solutions by josgarithmetic, ikleyn, advanced_Learner:
Answer by josgarithmetic(39623)   (Show Source): You can put this solution on YOUR website!
Use the most fundamental of Trigonometric identities:
Answer by ikleyn(52835)   (Show Source): You can put this solution on YOUR website!
.
Please help. I would like the answer in radians. Thanks!
2cos^2x + sinx -1 =0
~~~~~~~~~~~~~~~~~~~~~~~~

First what we need to do is to reduce the given equation to the quadratic equation for sin(x).
For it, use the identity cos^2(x) = 1-sin^2(x) and replace cos^2(x) in the equation by this expression. You will get

2*(1-sin^2(x) + sin(x) - 1 = 0,   or

2 - 2sin^2(x) + sin(x) - 1 = 0,   or

2sin^2(x) - sin(x) - 1 = 0.

Factor left side:

(2sin(x) + 1)*(sin(x) - 1) = 0.

Now the equation deploys in two independent equations:


1.  2sin(x) + 1 = 0  --->  sin(x) =   --->  x =   and/or  x = .


2.  sin(x) - 1 = 0  --->  sin(x) = 1  --->  x = .


Answer.  The solutions are  x = ,   and  .




Plot y =


Answer by advanced_Learner(501)   (Show Source): You can put this solution on YOUR website!
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since
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multiply both sides
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let =
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