SOLUTION: Prove that: Sin^4x =1�8 (3-4cos2x+cos4x)

Question 1045299: Prove that:
Sin^4x =1�8 (3-4cos2x+cos4x)
Found 2 solutions by advanced_Learner, Alan3354:
Answer by advanced_Learner(501) (Show Source): You can put this solution on YOUR website!
tommorrow
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Prove that:
Sin^4x =1�8 (3-4cos2x+cos4x)
-------
At x = 0:
0 = 1/(8*(3 - 4*1 + 1))
0 = 1/(8*0)
0 = 1/0
Not an identity.
RELATED QUESTIONS
Sin^4x = 1�8... (answered by robertb,advanced_Learner)
prove that... (answered by Edwin McCravy)
please help me prove identity for... (answered by jsmallt9)
What is the maximum and minimum of function y=cos4x-4cos2x+3 and its pi values (answered by Fombitz)
Please help me prove this equation ((1-cos4x)/(1+cos4x)) + 1 =... (answered by Aaragorn)
cos4x-sen4x/1-tan4x=cos4x (answered by Alan3354)
Prove the identity of... (answered by ikleyn)
Proving identities. How do I prove that: i) tan�(x) - sin�(x) = tan�(x) sin�(x) ii)... (answered by Edwin McCravy)
Prove: Cos4x = 8Cos^4(x) - 8Cos^2(x) + 1 Thank you in advance (answered by MathLover1)