SOLUTION: Sin^4x = 1÷8 (3-4cos2x+cos4x)

Algebra.Com
Question 1045298: Sin^4x = 1÷8 (3-4cos2x+cos4x)
Found 2 solutions by robertb, advanced_Learner:
Answer by robertb(5830)   (Show Source): You can put this solution on YOUR website!

=
=
=
=
=
=
= .

Answer by advanced_Learner(501)   (Show Source): You can put this solution on YOUR website!
.

RELATED QUESTIONS

Prove that: Sin^4x =1÷8... (answered by advanced_Learner,Alan3354)
prove that... (answered by Edwin McCravy)
please help me prove identity for... (answered by jsmallt9)
What is the maximum and minimum of function y=cos4x-4cos2x+3 and its pi values (answered by Fombitz)
cos4x-sen4x/1-tan4x=cos4x (answered by Alan3354)
evaluate... (answered by 4419875)
Please help me prove this equation ((1-cos4x)/(1+cos4x)) + 1 =... (answered by Aaragorn)
Prove the identity of... (answered by ikleyn)
cos2x-cos4x/sin2x+sin4x= a. cot x b. tan x c. sin x d. cos... (answered by Solver92311)