SOLUTION: Solve for x on the indicated interval [0,4]
2sin(2x)-sqr(3)=0
Algebra.Com
Question 1044672: Solve for x on the indicated interval [0,4]
2sin(2x)-sqr(3)=0
Found 2 solutions by MaxWong, robertb:
Answer by MaxWong(38) (Show Source): You can put this solution on YOUR website!
2 sin (2x)-=0
sin (2x) =
2x = arcsin sqrt3/2
x = 60 degrees / 2 = 30 degrees OR pi/6 radians.
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
x = , ,
RELATED QUESTIONS
Solve for x on the interval [0,2pi)
2sin(2pi)-sqr(3)=0
I recently asked this question,... (answered by ikleyn)
Find all solutions of the equation 2sin(2x)=sqr rt of 3 in the interval... (answered by stanbon)
Solve the equation for x, on the interval 0 is less than or equal to x and 2pi is greater (answered by Alan3354)
solve 2sin^2x+3sinx-4=0 in the interval... (answered by Alan3354)
Solve for x on the interval given:
a) 2sin^2x-5cosx+1=0 [0, pie]
b) sinx/2=0 [-pie,... (answered by Alan3354)
Solve for theta on the interval 0 <= theta <= 2pi.
2sin(theta)cos(theta) - cos(theta)... (answered by Fombitz)
2sin^2xcosx - cosx = 0 solve on the interval... (answered by lwsshak3)
Solve for x:... (answered by Boreal)
graph y= 2sin(2x - pi) on the interval 0 <= x <=... (answered by nyc_function)