SOLUTION: solve for x on the interval [0,2pi) 3cosx-1=2 first i isolated cosx and got cosx=1 i did cos^-1(1) to find x and got 0 but i am being told that 0 is not the correct answer. help

Question 1044657: solve for x on the interval [0,2pi)
3cosx-1=2
first i isolated cosx and got cosx=1
i did cos^-1(1) to find x and got 0 but i am being told that 0 is not the correct answer. help me please?
Answer by ikleyn(52787) (Show Source): You can put this solution on YOUR website!
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solve for x on the interval [0,2pi)
3cosx-1=2
first i isolated cosx and got cosx=1
i did cos^-1(1) to find x and got 0 but i am being told that 0 is not the correct answer. help me please?
~~~~~~~~~~~~~~~~~~~~~~~~~

3cos(x) - 1 = 2  --->

3cos(x) = 2 + 1  --->  3cos(x) = 3  --->  cos(x) = 1  --->  x = 0 (zero).

The only solution is x = 0 (zero).

There is no other solutions.

0 (zero) IS CORRECT ANSWER.

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