SOLUTION: Solve sin^2θ − 5cosθ = 5 for 0°≤θ≤360°

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Question 1042505: Solve sin^2θ − 5cosθ = 5 for 0°≤θ≤360°
Answer by ikleyn(52865)   (Show Source): You can put this solution on YOUR website!
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Solve sin^2(theta) - 5cos(theta) = 5 for 0° <= theta < 360°.
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Replace  by  to have the equation for  only. You will get

 = ,  or

 = .

Factor left side:

 = .

Then the equation deploys in two equations:

1)   = ,  or   = ,  which has no solutions,  and

2)   = ,  or   = ,  which has the solution  = 180°.

Answer.  The solution is  = 180°.


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