SOLUTION: Sin10*cos20*tan40*tan50*cosec70*sec80=1

SOLUTION: Sin10cos20tan40tan50cosec70*sec80=1

Algebra.Com

Question 1041169: Sin10*cos20*tan40*tan50*cosec70*sec80=1
Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
Sin10*cos20*tan40*tan50*cosec70*sec80=1
(sin10⁰)(cos20⁰)(tan40⁰)(tan50⁰)(cosec70⁰)(sec80⁰) = 1
True

RELATED QUESTIONS
sin10�cot 20�cos 30�tan40�tan50�cosec 60�cot70�sec 80�=1... (answered by ikleyn)

Graph {{{ y=(1/2)tan40... (answered by Alan3354)

find the product 2(cos10 degrees + i sin10 degrees)4(cos20 degrees + i sin20 degrees)... (answered by rapaljer)

(1+COS20)(1+COS60)(1+COS100)(1+COS140)= ? (answered by MathLover1)

tan20�+2... (answered by srinivas.g)

Solution of... (answered by ikleyn)

tan20*tan80*tan40 (answered by Alan3354)

Cos20�-cos320�+cos100� (answered by ikleyn)

sec80>1 how do I proof... (answered by ikleyn)