SOLUTION: Solve for the exact solutions in the interval
[0,2π)
1/2tan^2(x)=1−sec(x)
I got 4.37 but apparently there's another solution ?
Algebra.Com
Question 1041001: Solve for the exact solutions in the interval
[0,2π)
1/2tan^2(x)=1−sec(x)
I got 4.37 but apparently there's another solution ?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Solve for the exact solutions in the interval
[0,2π)
1/2tan^2(x)=1 - sec(x)
Sub (sec^2 - 1) for tan^2
RELATED QUESTIONS
Solve for the exact solutions in the interval [0,2π)
cos(2x)=cos(x)
I got 0 but... (answered by Alan3354)
Solve the equation for exact solutions over the interval [0, 2π).
cos^2 x + 2 cos (answered by ikleyn)
Solve the equation for exact solutions over the interval [0, 2π).
cos2x + 2 cos x (answered by ikleyn)
Is this right? please check exact value of tan(5π/3)sec(-5π/6) and other?... (answered by Alan3354)
Solve this equation graphically on the interval [0, 2π]. Sketch the graph and list... (answered by Alan3354)
Find all solutions of the equation in the interval [0, 2π). (Enter your answers as a (answered by Alan3354)
Find all solutions of the equation in the interval [0, 2π)
sin(x + π/4)... (answered by lwsshak3)
Find the exact solutions in the interval [ 0 , 2π] for cos 2x – cos x =... (answered by lwsshak3)
Find all solutions of the equation in the interval [0, 2π). (Enter your answers as a (answered by stanbon)