SOLUTION: Solve for x: 3logx + 1/logx = 4

Question 1040871: Solve for x:
3logx + 1/logx = 4
Found 2 solutions by addingup, MathTherapy:
Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
Solve for x:
3log(x) + 1/log(x) = 4
1/(log(x))+3*log(x) = 4
Substitute y = log(x):
3y+1/y = 4
(3y^2+1)/y = 4
3y^2+1 = 4y
3y^2-4y+1 = 0
(y-1)(3y-1) = 0
y-1 = 0 or 3y-1 = 0
y = 1 or 3y-1 = 0
Substitute back for y = log(x):
log(x) = 1 or 3y-1 = 0
take exp of both sides:
x = e or 3y-1 = 0
x = e or 3y = 1
x = e or y = 1/3
x = e or log(x) = 1/3
x = e or x = e^(1/3)
Answer by MathTherapy(10555) (Show Source): You can put this solution on YOUR website!

Solve for x:
3logx + 1/logx = 4

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