SOLUTION: Solve graphically.
2^x+3^x=x^2+x^3
The solution is the interval ?
or
The​ solution(s) is/are x= ?
* I don't have a graphing calculator so i need the answer *
Algebra.Com
Question 1039479: Solve graphically.
2^x+3^x=x^2+x^3
The solution is the interval ?
or
The solution(s) is/are x= ?
* I don't have a graphing calculator so i need the answer *
Found 2 solutions by Alan3354, Boreal:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
dl the FREE graph software at
www.padowan.dk
----
Use Ins, then enter 2^x + 3^x - x^2 - x^3
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Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
Write as 2^x+3^x-x^2-x^3, and set it equal to zero.
x=2.29 and x=3.23
check
4.89+12.38=5.24+12.00
17.27=17.24, within rounding error
------------------
9.38+34.76=10.43+33.70
44.14=44.13, within rounding error.
{2.29,3.23} These are discrete points.
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