SOLUTION: Find sinX if sin2X = 2/3 with the 2x between 90 and 180 degrees.

Question 1038415: Find sinX if sin2X = 2/3 with the 2x between 90 and 180 degrees.
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
as far as i can tell, ......
sin(2x) = 2/3
this means that arcsin(2/3) = 2x.
using your scientific calculator, this means that 2x = 41.8103149 degrees.
since 2x is in the second quadrant, this means that 2x = 180 - 41.8103149 degrees.
that makes 2x = 138.1896851 degrees.
solve for x to get x = 69.09484255 degrees.
if this is correct, then sin(x) = sin(69.09484255) = .934172359.

RELATED QUESTIONS
Arrange the steps in the correct order to solve this trigonometric equation.... (answered by Solver92311,ikleyn)

If cosx=-3/5, and x is in between 180 and 360 degrees, find the value of... (answered by Boreal,ikleyn)

find all the angles between 0� and 180� for which sin2x + 3/4(cos2x) =... (answered by stanbon)

what is the exact value of sin2x, cos2x and tan2x if... (answered by lwsshak3)

find sin 0 if cos 0=-2/3 and 90 degree<0>180... (answered by stanbon)

Find {{{ sin2x }}} if {{{ secx=-4 }}} and {{{ sinx<0... (answered by Edwin McCravy)

find sin2x, cos2x, and tan2x if sinx= {{{-2/sqrt(5)}}} and x terminates in quadrant... (answered by lwsshak3)

Find sin2x,cos2x,tan2x if sinx=3/sqrt10 and x terminates in quadrant... (answered by lwsshak3)

Find sin2x, cos2x, tan2x if sinx= -8/17 and x terminates in quadrant III... (answered by ikleyn)