SOLUTION: Two ships leave a port, sailing at 16 km/h and 12 km/h. The angle between their directions of travel from the port is 40�. How far apart are the ships after 3 hours? Include a diag

Question 1038034: Two ships leave a port, sailing at 16 km/h and 12 km/h. The angle between their directions of travel from the port is 40�. How far apart are the ships after 3 hours? Include a diagram.
16(3) = 48
18(3) = 54
c^2 = 48^2+54^2-2(48)(54)cos40�
c^2 = 2304+2916-5184(cos40�)
c^2 = 5220-3971.17
c = 1248.83 km
I believe I have the answer right but I am having trouble with sketching the diagram correctly. Help would be appreciated.
Thank you
Found 2 solutions by Boreal, MathTherapy:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
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Scalene triangle, but the distance can't be that large, for the ships, even if going in opposite directions would be only 84 km apart at 3 hours. The 1248.83 number is for c^2; the square root is 35.34 km.
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!

Two ships leave a port, sailing at 16 km/h and 12 km/h. The angle between their directions of travel from the port is 40�. How far apart are the ships after 3 hours? Include a diagram.

Where did you get 18 from?
Based on the triangle inequality theorem, the third side, or distance apart from each other should be > 12 km, but < 84 km
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