Question 1037917: A ladder is inclined at an angle of 60° against a wall. If the foot of the ladder is 8 m from the wall, how far up the wall does the ladder reach?
Tan60°= x/8
Tan60°/1 = x/8
x= 8(Tan60°)
x= 13.8564
x= 13.9 m
Wondering if I'm on the right track.
Thank you
Found 3 solutions by addingup, josgarithmetic, MathTherapy:
Answer by addingup(3677)   (Show Source):
You can put this solution on YOUR website! You are dealing with a very special type of triangle. It's a right triangle, so we know one angle is 90. The other, the problem says, is 60. Therefore the last must be 180-90-60 = 30
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This is called a 30-60-90 angle. Among its properties:
You can find the long leg, or as your problem says "how far up the wall the ladder reaches", by multiplying the short leg times the square root of 3:
8*sqrt3 = 13.86m up the wall.
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By the way, the hypotenuse - the length of the ladder itself, which is at a slant like this /, in a 30-60-90 problem is always two times the shortest leg, so your ladder measures 8*2 = 16m
Answer by josgarithmetic(39620)  (Show Source):
Answer by MathTherapy(10553)  (Show Source):
You can put this solution on YOUR website!
A ladder is inclined at an angle of 60° against a wall. If the foot of the ladder is 8 m from the wall, how far up the wall does the ladder reach?
Tan60°= x/8
Tan60°/1 = x/8
x= 8(Tan60°)
x= 13.8564
x= 13.9 m
Wondering if I'm on the right track.
Thank you
You're perfectly correct! Good job!!!
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