SOLUTION: Sketch a picture and solve the triangle (find all side lengths and angle measures to the nearest tenth) using Law of Cosines and/or Law of Sines. Show all your work. (hint: t

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Question 1037821: Sketch a picture and solve the triangle (find all side
lengths and angle measures to the nearest tenth) using Law
of Cosines and/or Law of Sines. Show all your work. (hint:
this is an SSA scenario with two solutions, so you’ll need
to sketch and solve two triangles)
∆ABC with m∠A = 38 and AB = 6.3 and BC = 4.2

Answer by Edwin McCravy(20065)   (Show Source): You can put this solution on YOUR website!
∆ABC with m∠A = 38° and AB = 6.3 and BC = 4.2

Using law of sines:













∠C is an acute (QI) angle and ∠AC'B is an 
obtuse (QII) angle.  They have the same sine and are
supplementary.

Using the inverse sine feature of our calculator,

∠C = 67.44208077°

so ∠AC'B = 180°-67.44208077° = 112.5579192°

To find side AC and AC', we use the law of cosines:



Swap sides:



Rearrange terms and a factor with 0 on the right:







Use the quadratic formula





Using the + gives us AC = 6.575659859
Using the - gives us AC' = 3.353275637

We can find ∠ABC and ∠ABC' by adding the 
two angles we now know and subtracting from 180°.

You can finish that part.

Edwin


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