SOLUTION: 5sin^2 90deg + 2cos^2 270deg

SOLUTION: 5sin^2 90deg + 2cos^2 270deg - tan 360deg

Question 1037230: 5sin^2 90deg + 2cos^2 270deg - tan 360deg
Answer by ikleyn(52943) (Show Source): You can put this solution on YOUR website!
.
5sin^2(90�) + 2cos^2(270�) - tan(360�)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

sin(90�) = 1; cos(270�) = 0; tan(360�) = 0.

Therefore, 5sin^2(90�) + 2cos^2(270�) - tan(360�) = 5*1 + 2*0 -0 = 5.

RELATED QUESTIONS
3cos^2 thetha+2cos theta = 1 interval [0deg,360deg) (answered by MathLover1,ikleyn,math_tutor2020)

if 5sin^2 theta+4cos^2 theta=9/2 then tan... (answered by Boreal,ikleyn)

Verify that each equation is an identity (2cos^2 (X/2)) (tan X) = tan X + sin X... (answered by lwsshak3)

3sin^2 theta -5sin theta +2 =... (answered by Edwin McCravy,MathTherapy)

(tan(theta)-cot(theta))/(tan(theta)+cot(theta))+2cos^2(theta)=1 (answered by Aswathy)

Please help me verify the identity: 1-tan^2t/1+tan^2t=... (answered by lwsshak3)

Solve for x if: 5sin^2x-5cosx=-3 ; x is between 0deg and 360deg (answered by Theo)

Verify that each equation is an identity. 2cos^2(theta)-1=... (answered by lwsshak3)

Solve: cos^2 theta - sin^2 theta = rad3/2 for theta in the domain [0deg,... (answered by lwsshak3,jsmallt9)