Unclear. Read your post. Try to understand. The re-formulate and re-post.
My response: OK. I found an appropriate Figure from my archive (on the right), and I will use it as an illustration, although it is not in the scale (sorry). So, BC represents the ladder, its length is 7 ft. DE and FE are of 1 ft length each, according to the condition (! not in the scale !). We need to find the length of AC. Let "x" be the length of FC and "y" be the length of DB. Consider the triangles EFC and BDE. They are similar. From the similarity, you have a proportion so y = |
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