SOLUTION: Find all solutions of the equation in the interval [0, 2pi). -sinx=-cos^2x-1 Write your answer in radians in terms of pi.

SOLUTION: Find all solutions of the equation in the interval [0, 2pi). -sinx=-cos^2x-1 Write your answer in radians in terms of pi.

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Question 1034388: Find all solutions of the equation in the interval [0, 2pi).
-sinx=-cos^2x-1
Write your answer in radians in terms of pi.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
-sinx=-cos^2x-1
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cos^2 = 1 - sin^2

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