Question 1034092: Find tan t given that sin t=3/5 and cot t < 0 Found 3 solutions by josmiceli, stanbon, MathTherapy:Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website! Thinking just about signs, it is given that
sin(t) is positive and cot(t) is negative.
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The sin function is positive in the
1st and 2nd quadrants
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The cot function is negative in the
2nd and 4th quadrants
-------------------- must be an angle in the 2nd
quadrant
The horizontal component is
since
-------------------- Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website! Find tan t given that sin t=3/5 and cot(t) is negative, t is in QII
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Since sin = y/r, y = 3 and r = 5
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Then x = -sqrt[5^2-3^2] = -4
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tan(t) = y/x = -4/5
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Cheers,
Stan H. Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
Find tan t given that sin t=3/5 and cot t < 0
sin is positive (> 0), and cot is negative (< 0), so t is in the 2nd quadrant. Also since cot is < 0, tan will also be < 0
Since y = 3 and r = 5, this is a 3-4-5 Pythagorean triple. Hence, x = - 4 (x is < 0 in the 2nd quadrant)