SOLUTION: Calculate the value of x, if ((Sin^2)x) + 2sinx - 2cosx - (1/2)sin2x = 0

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Question 1031125: Calculate the value of x, if
((Sin^2)x) + 2sinx - 2cosx - (1/2)sin2x = 0
Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Calculate the value of x, if
((Sin^2)x) + 2sinx - 2cosx - (1/2)sin2x = 0
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((Sin^2)x) + 2sinx - 2cosx - sinx*cosx = 0
sin*(sin + 2) - cos*(sin + 2) = 0
(sin - cos)*(sin + 2) = 0
x = -2 *** No real solution, ignore.
-------------
sin = cos
x = pi/4, 9pi/4 + 2n*pi, n = any integer
Answer by ikleyn(52915)   (Show Source): You can put this solution on YOUR website!
.
Calculate the value of x, if
((Sin^2)x) + 2sinx - 2cosx - (1/2)sin2x = 0
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 

After you get 

sin(x) = cos(x),

as the previous tutor got, the continuation is

tan(x) = 1.

Hence, x =   or/and  x = , k = 0, +/-1, +/- 2, . . .


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