SOLUTION: the area of a square is 81 - 72 x + 16 x^2 if x must be a positive integer, what is the least possible measure for the perimeter of the square
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Question 1030553: the area of a square is 81 - 72 x + 16 x^2 if x must be a positive integer, what is the least possible measure for the perimeter of the square
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
==>
==> Perimeter is
If x = 1, P = 20,
If x = 2, P = 4,
If x = 3, P = 12,
If x = 4, P = 28, etc., ...
Therefore the least possible measure for the perimeter of the square is 4.
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