SOLUTION: {{{3*cos(beta) + 3}}} = {{{2*sin^2(beta)}}}

SOLUTION: {{{3cos(beta) + 3}}} = {{{2sin^2(beta)}}}

Question 1030398: =
Answer by ikleyn(52802) (Show Source): You can put this solution on YOUR website!
.

 = .

Replace    by  .  You will get

 = ,   or

 = ,   or

 = ,   or  (after factoring left side)

 = .


It gives you two equations.


1)   =   --->   =   --->  beta =   or  beta = ,  k = 0, +/-1, +/-2, . . . 


2)   =   --->   =   --->  beta =  = ,  k = 0, +/-1, +/-2, . . .

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