SOLUTION: √3*sin(x/2)+cos(x/2)=0
(π≤x<4π)
Algebra.Com
Question 1030368: √3*sin(x/2)+cos(x/2)=0
(π≤x<4π)
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
What do you want to do with this equation?
John

My calculator said it, I believe it, that settles it
RELATED QUESTIONS
√3*sin(x/2)+cos(x/2)=0... (answered by ikleyn)
Solve the cos x-1 =0 on the interval 0≤x≤pi/2
x+ π/3
x=0
x=π/6... (answered by richard1234)
Solve {{{sin(2x)-cos(x)=0}}} given that 0 ≤ x <... (answered by KMST,rothauserc)
a. Let
f (x) =√(49 - x^2)/x
and g(t) = 7 sin t for 0 ≤ t < π/2.... (answered by stanbon)
-sin(π/2-x)=√3*sin(x)
(0≤x<π)
(answered by solver91311,ikleyn)
How many points in the interval 0 ≤ x ≤ 2π satisfy the equation cos 2x = (answered by stanbon)
How many points in the interval 0 ≤ x ≤ 2π satisfy the equation cos 2x = (answered by stanbon)
x = 6 sin t
y = 6 cos t, 0 ≤ t ≤ 2π
Graph these parametric... (answered by stanbon)
Solve the following equations given that: 0 ≤ x < 2π
(a)... (answered by Alan3354)