SOLUTION: i need to express cos 632 degrees in terms of the same function of a postive acute angle

Question 1030060: i need to express cos 632 degrees in terms of the same function of a postive acute angle
Found 2 solutions by fractalier, josmiceli:
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Okay. Since the cosine repeats every 360, we can subtract 360 off twice and get
cos 632 = cos 272 = cos (-88)
Since the cosine function is an even function,
cos (-x) = cos x
so that
cos (-88) = cos 88
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Start at 0 degrees and turn the unit vector
360 degrees at a time counter clockwise
-------------------
After a 360 degree turn,
degrees are left
and the unit vector is back at 0 degrees
-------------------
Now turn the unit vector 270 degrees, ( going counter clockwise)
which is 90 degrees past 180 degree location
and 2 degrees are left, which will
put you in the 4th quadrant
--------------------
If you do any trig functions of this angle,
the angle will be degrees
to the 0 degree location in the 4th quadrant
--------------------
Some trig functions are negative in the 4th quadrant,
cos( 272 ) = (+) cos( 88 )
sin( 272 ) = (-) sin( 88 )
--------------------
hope this helps

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