SOLUTION: 1-sin^2x/1-sinx=cscx+1/cscx
Algebra.Com
Question 1029092: 1-sin^2x/1-sinx=cscx+1/cscx
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
(1-sin^2x)/(1-sinx) = (cscx+1)/cscx
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(1+sin(x)) = 1 + (1/csc(x))
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1+sinx = 1 + sin(x)
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Cheers,
Stan H.
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