SOLUTION: sin^-1{{{ sqrt( 3 ) /2 ) }}}
cos^-1{{{-sqrt( 3 ) /2) }}}
tan^-1(-1)
cos^-1{{{cos(4( pi ))/3}}}
sin{{{tan^-1(7/24)}}}
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Question 1028759: sin^-1
cos^-1
tan^-1(-1)
cos^-1
sin
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
sin^-1[sqrt( 3 ) /2 )] = pi/3
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cos^-1[-sqrt( 3 ) /2)] = (5/6)pi
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tan^-1(-1) = (7/4)pi
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cos^-1[cos(4( pi ))/3}] = (4/3)pi
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sin[tan^-1(7/24)]
tan = y/x
y = 7 and x = 24
Then r = sqrt[24^2+7^2] = 25
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Ans:: sin = x/r = 7/25 = 0.28
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Cheers,
Stan H.
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