SOLUTION: tanA/1+cosA + sinA/1- cosA = cotA + cosecA - secA

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Question 1027365: tanA/1+cosA + sinA/1- cosA = cotA + cosecA - secA
Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
First you should learn about the PEMDAS order of operations,
which requires that if you type algebra all on one line,
if a numerator of denominator contains any additions,
subtractions, multiplications, or divisions, you MUST put a
left parenthesis "(" before it to show where it begins and 
a right parenthesis ")" after it to show where it ends,
because when it's typed all on one line it all runs together
and you must do that to indicate which terms are parts of
which numerators and which denominators or whether they are 
not parts of either.  So instead of this

tanA/1+cosA + sinA/1- cosA = cotA + cosecA - secA

you should have written this:

tanA/(1+cosA) + sinA/(1-cosA) = cotA + cosecA - secA 

which means this:



But this is not an identity and it also has no solutions.

Did you copy it right?

Edwin





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