SOLUTION: solve the equation on the interval [0,2pi] tan^2(x)=tan^2(x)sec(x)

Question 1024815: solve the equation on the interval [0,2pi]
tan^2(x)=tan^2(x)sec(x)
Answer by ikleyn(52790) (Show Source): You can put this solution on YOUR website!
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solve the equation on the interval [0,2pi]
tan^2(x)=tan^2(x)sec(x)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

 =   --->

 -  = ,

 = .


So this equations breaks down into two independent equations


1.   =   --->  tan(x) = 0  --->  x = 0 and x = .


2.   =   --->  = 0  --->  cos(x) = 1  --->  x = 0. 


The entire set of solution of the original equation in the given interval consists of two numbers:  0  and  .

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