SOLUTION: Find the cube roots of 27(cos 279° + i sin 279°).
*Please show your work, so I can understand it:)
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Question 1024125: Find the cube roots of 27(cos 279° + i sin 279°).
*Please show your work, so I can understand it:)
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find the cube roots of 27(cos 279° + i sin 279°)
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279/3 = 93
(279 + 360)/3 = 213
(279 + 720)/3 = 333
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--> 3cis(93), 3cis(213), 3cis(333)
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cis = cos + i*sin
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