SOLUTION: solve equations (solve over the interval [0,2pi)) sin2x= root2/2

SOLUTION: solve equations (solve over the interval [0,2pi)) sin2x= root2/2

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Question 1023509: solve equations (solve over the interval [0,2pi))
sin2x= root2/2
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
solve equations (solve over the interval [0,2pi))
sin2x= root2/2
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2x = pi/4, 3pi/4, 9pi/4, 11pi/4
x = 1/2 of those.

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