SOLUTION: Suppose tan(alpha) = {{{5/6}}} and alpha terminates in Quadrant III. Without simplifying any square roots, sin(alpha) = cos(alpha) = cot(alpha) = sec(alpha)

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Question 1022333: Suppose tan(alpha) = and alpha terminates in Quadrant III.
Without simplifying any square roots,
sin(alpha) =
cos(alpha) =
cot(alpha) =
sec(alpha) =
csc(alpha) =

Found 3 solutions by Alan3354, ikleyn, MathTherapy:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Not clear

Answer by ikleyn(52788)   (Show Source): You can put this solution on YOUR website!
.
Suppose tan(alpha) =   and alpha terminates in Quadrant III.
Without simplifying any square roots, calculate 


sin(alpha) =   =  =  = .
               
              The sign "-" (minus) was chosen because the angle  terminates in Quadrant III.

               
cos(alpha) =   =  =  = .


              The sign "-" (minus) was chosen because the angle  terminates in Quadrant III.


cot(alpha) =   = .


sec(alpha) =   = .


csc(alpha) =   = .

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Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
Suppose tan(alpha) = and alpha terminates in Quadrant III.
Without simplifying any square roots,
sin(alpha) =
cos(alpha) =
cot(alpha) =
sec(alpha) =
csc(alpha) =

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