SOLUTION: What is the equation of the circle passing through the point (6,5) and centered at (3,-4)? What are the coordinates of the center of a circle whose equation is x2 + y2 � 16x + 6

Question 1020736: What is the equation of the circle passing through the point (6,5) and centered at (3,-4)?
What are the coordinates of the center of a circle whose equation is x2 + y2 � 16x + 6y + 53 = 0?
Which ordered pair is in the solution set of the system of equations shown below?
y2 � x2 + 32 = 0
3y � x = 0
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Three different questions. I will help with just the second question.

This way in pure text:
x^2+y^2�16x+6y+53=0

-----in case not fully rendering, x^2+y^2-16x+6y+53=0

Choose correct terms to complete the squares as/if necessary.

-
Center point of the circle is (8,-3).

How to complete the square is described and discussed here:
http://www.algebra.com/my/Completing-the-Square-to-Solve-General-Quadratic-Equation.lesson?content_action=show_dev
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