SOLUTION: An 18-newton force acting at 56� and a 23-newton force acting at 142� act concurrently on an object. What is the magnitude and direction of the resultant vector?

Question 1019904: An 18-newton force acting at 56� and a 23-newton force acting at 142� act concurrently on an object. What is the magnitude and direction of the resultant vector?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
An 18-newton force acting at 56� and a 23-newton force acting at 142� act concurrently on an object. What is the magnitude and direction of the resultant vector?
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Let the resultant be (x,y)::
x = 18cos(56)+23cos(142) = -8.06
y = 18sin(56)+23sin(142) = 29.08
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magnitude = sqrt[8.06^2+29.08^2] = 30.18 newtons
direction = arctan(29.08/-8.06) = -74.51 + 360 = 285.49 degrees
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Cheers,
Stan H.
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