SOLUTION: Solve for (0 lesser than or equal to theta < 2pi ) {{{ sin(theta) = sin^2 (theta) }}} Thank you!!

Question 1015198: Solve for (0 lesser than or equal to theta < 2pi )

Thank you!!
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
For any equation x = x^2, x = 0 or x = 1.
Thus (using x for theta)
sin x = 0 and x = 0
sin x = 1 and x = pi/2
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