SOLUTION: prove that sin^6 theta = -1/32 (cos 6 theta - 6 cos 4 theta + 16 cos 2 theta

SOLUTION: prove that sin^6 theta = -1/32 (cos 6 theta - 6 cos 4 theta + 16 cos 2 theta - 10).

Question 1011603: prove that sin^6 theta = -1/32 (cos 6 theta - 6 cos 4 theta + 16 cos 2 theta - 10).
Answer by Edwin McCravy(20063) (Show Source): You can put this solution on YOUR website!


It isn't true!  So instead of proving it, let's disprove it:



We'll just prove that it isn't true by substituting 





sin(0) = 0 and cos(0) = 1, so









So that is false.  Did you perhaps copy it wrong?

Edwin

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