SOLUTION: sin2a/1-cos^2a x sin2a/cosa=4cosa
Algebra.Com
Question 1010874: sin2a/1-cos^2a x sin2a/cosa=4cosa
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
sin2a/1-cos^2a x sin2a/cosa=4cosa
2sina*cosa/sin^2a * 2sina*cosa/cos a =
4*sin^2a*cos^2a / sin^2a* cosa =
4 cos^2 a / cos a =
4 cos a = 4 cos a
RELATED QUESTIONS
sin2a/1-cos^2a x sin2a/cos2a=... (answered by fractalier)
sin2A=? (answered by Alan3354)
Prove that... (answered by robertb)
Please prove: ((cos2A)/(cosA+sinA)^3) =... (answered by Cromlix)
Prove that: ((cos2A)/(cosA+sinA)^3) =... (answered by Cromlix)
How do you prove... (answered by Alan3354)
prove sin(5A) + sin(2A) - sin(A) = sin2A(2cos3A +... (answered by Alan3354)
Prove (SinA+CosA)^2=1+Sin2A
Thank... (answered by richard1234)
2... (answered by Alan3354)