The double-argument formula says that= . (See, for example, the lesson Trigonometric functions of multiply argument in this site). Substitute it into the original equation, and you will get + = . Now factor it: . = . Thus you get two equations: 1) = , which has two solutions = and in the given interval for . 2) = , or = , which has two solutions = and . Answer. The solutions are = , , and .