SOLUTION: An airplane has an airspeed of 500 kilometers per hour (kn/h) bearing N45E. The wind velocity is 60 km/h in the direction N30W. Find the resultant representing the path of the plan

Question 1005814: An airplane has an airspeed of 500 kilometers per hour (kn/h) bearing N45E. The wind velocity is 60 km/h in the direction N30W. Find the resultant representing the path of the plane relative to the ground. What is the groundspeed of the plane? What is its direction?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
An airplane has an airspeed of 500 kilometers per hour (kn/h) bearing N45E. The wind velocity is 60 km/h in the direction N30W. Find the resultant representing the path of the plane relative to the ground. What is the groundspeed of the plane? What is its direction?
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2 sides of the triangle are a = 500 and b = 60.
The included angle C is 75 degs (if the wind is moving TO N30W. Wind direction is given in the direction it's from in aviation.)
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The groundspeed is the 3rd side, side c.
Use the Cosine Law to find it.
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Then use the Law of Sines to find angle B. Subtract angle B from 045 to find the ground track.

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