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put this solution on YOUR website!with complex numbers, the real part is on the horizontal (x) axis
__ and the imaginary part is on the vertical (y) axis
so sqrt(3) on the x and 1 on the y forms two sides of a right triangle
__ the 3rd side is the hypotenuse; which is the polar radius
using Pythagoras, r^2=x^2+y^2 __ r^2=[sqrt(3)]^2+1^2 __ r^2=3+1 __ r=2
the tangent of the polar angle is [imaginary]/[real] or y/x
__ tan(Θ)=1/sqrt(3) __ Θ=30º or π/6 radians
