|
Tutors Answer Your Questions about Triangles (FREE)
Question 121232: . (3 pts) A small area in front of a building is triangular in shape. The perimeter of the triangle is 37 meters. The second side is one-half of the first side in length. The third side is 3 meters less than the first side. Find the length in meters of each side of the triangular region.
37= (½ * x) + (x-3)
37= 1/2x + (x-3)
39.5=2x
X=19.75
1st side= 19.75 meter
2nd side= 0.5 * 19.75 = 9.875 meters
3rd side= 19.75-3= 16.75 meters
Click here to see answer by stanbon(26297)   |
Question 121459: Two sides of an isosceles triangle each measure 10 inches and the vertex angle measures 40 degrees. Find the length of the altitude to the base to the nearest tenth of an inch.
Answers:
a) 9.4 inches
b) 909 inches
c) 10.2 inches
d) 10.8 inches
e) 11.3 inches
Which is the correct answer?
Click here to see answer by curiousgeorge(1) |
Question 121466: Please help me pick the correct answer.
2 sides of an isosceles triangle each measure 10 inches and the vertex angle measures 40 degrees. Find the length of the altitude to the base to the nearest tenth of an inch.
Answers:
a) 9.4 inches
b) 9.9 inches
c) 10.2 inches
d) 10.8 inches
e) 11.3 inches
Click here to see answer by algebrapro18(206) |
Question 121545: Please help me figure this out.
A triangle has an area of 24cm^2. By what scale factor must each of the
dimension of the triangle be multiplied to give a similar triangle so
that the area is increased by 360cm^2?
Answers:
a) 3.9
b) 4
c) 8
d) 15
e) 16
Click here to see answer by solver91311(5072)  |
Question 121820: Hello,
I have a question that I am having a lot of trouble with. I'll give you the question and try to explain (as best as I can) my working out so far and hopefully you'll be able to understand it and give me a detailed explanation of the answer. :^)
I think you might need a diagram to visualise the whole thing which I cannot actually draw, however, I'll do my best to describe it. (If you would like a similar picture I checked Google Images and did find an image that closely resembled what the question was. Except for the circle at the base of the larger circle, everything is correct. Insert the measurements and that's
how it looks like. The link is: http://mimosa.cnice.mecd.es/~jcolon/tangen.gif
THE QUESTION
Here it is:
Imagine a circle and a isosceles triangle is in it, each of its vertices touching the edges of the circle. The top vertice is labelled P and the two bottom vertices from left to right is labelled Q and R. (I hope you can either visualise it or sketch it on a piece of paper) QR = 18 and PQ = PR = 15. The questions asks me/you: What is the radius of the circle?
MY WORKING OUT
I drew a line bisecting the triangle PQR in the way you told me to and extended it down to the diameter of the circle. Then I labelled the diameter PS and the intersection of PS and QR: T. I now have two right-angled triangles where I can label each side length a, b and c (the hypotenuse).
a = the side length I need to find
b = T-R or T-Q (halve 18 [Q-R) = 9
c = hypotenuse (15)
I then applied the Pythagorean Theorem to find (a) which is the side length I need to find, n amelly the segment PT. Using the Pythagorean Theorem PT = 12. All I needed to find now was the segment TS and in order to do that I needed to find the segment QS, and if I connect them I form another two triangles (QTS) and (PSQ) and I can use the sides of PTQ to work it out. But I'm stuck. I
don't know where to go from here.
Please help, because Im not sure what to do next. Do I have to understand trigonometry, or geometry or more about triangles to solve it? I was told by my teacher there is a special relationship between the triangles PQS, PTQ and QTS. But I don't know what.
Thanks,
Jasmine (13)
Click here to see answer by oscargut(682)  |
Question 121820: Hello,
I have a question that I am having a lot of trouble with. I'll give you the question and try to explain (as best as I can) my working out so far and hopefully you'll be able to understand it and give me a detailed explanation of the answer. :^)
I think you might need a diagram to visualise the whole thing which I cannot actually draw, however, I'll do my best to describe it. (If you would like a similar picture I checked Google Images and did find an image that closely resembled what the question was. Except for the circle at the base of the larger circle, everything is correct. Insert the measurements and that's
how it looks like. The link is: http://mimosa.cnice.mecd.es/~jcolon/tangen.gif
THE QUESTION
Here it is:
Imagine a circle and a isosceles triangle is in it, each of its vertices touching the edges of the circle. The top vertice is labelled P and the two bottom vertices from left to right is labelled Q and R. (I hope you can either visualise it or sketch it on a piece of paper) QR = 18 and PQ = PR = 15. The questions asks me/you: What is the radius of the circle?
MY WORKING OUT
I drew a line bisecting the triangle PQR in the way you told me to and extended it down to the diameter of the circle. Then I labelled the diameter PS and the intersection of PS and QR: T. I now have two right-angled triangles where I can label each side length a, b and c (the hypotenuse).
a = the side length I need to find
b = T-R or T-Q (halve 18 [Q-R) = 9
c = hypotenuse (15)
I then applied the Pythagorean Theorem to find (a) which is the side length I need to find, n amelly the segment PT. Using the Pythagorean Theorem PT = 12. All I needed to find now was the segment TS and in order to do that I needed to find the segment QS, and if I connect them I form another two triangles (QTS) and (PSQ) and I can use the sides of PTQ to work it out. But I'm stuck. I
don't know where to go from here.
Please help, because Im not sure what to do next. Do I have to understand trigonometry, or geometry or more about triangles to solve it? I was told by my teacher there is a special relationship between the triangles PQS, PTQ and QTS. But I don't know what.
Thanks,
Jasmine (13)
Click here to see answer by Fombitz(2113)  |
Question 121821: Hello,
I have a question that I am having a lot of trouble with. I'll give you the question and try to explain (as best as I can) my working out so far and hopefully you'll be able to understand it and give me a detailed explanation of the answer. :^)
I think you might need a diagram to visualise the whole thing which I cannot actually draw, however, I'll do my best to describe it. (If you would like a similar picture I checked Google Images and did find an image that closely resembled what the question was. Except for the circle at the base of the larger circle, everything is correct. Insert the measurements and that's
how it looks like. The link is: http://mimosa.cnice.mecd.es/~jcolon/tangen.gif
THE QUESTION
Here it is:
Imagine a circle and a isosceles triangle is in it, each of its vertices touching the edges of the circle. The top vertice is labelled P and the two bottom vertices from left to right is labelled Q and R. (I hope you can either visualise it or sketch it on a piece of paper) QR = 18 and PQ = PR = 15. The questions asks me/you: What is the radius of the circle?
MY WORKING OUT
I drew a line bisecting the triangle PQR in the way you told me to and extended it down to the diameter of the circle. Then I labelled the diameter PS and the intersection of PS and QR: T. I now have two right-angled triangles where I can label each side length a, b and c (the hypotenuse).
a = the side length I need to find
b = T-R or T-Q (halve 18 [Q-R) = 9
c = hypotenuse (15)
I then applied the Pythagorean Theorem to find (a) which is the side length I need to find, n amelly the segment PT. Using the Pythagorean Theorem PT = 12. All I needed to find now was the segment TS and in order to do that I needed to find the segment QS, and if I connect them I form another two triangles (QTS) and (PSQ) and I can use the sides of PTQ to work it out. But I'm stuck. I
don't know where to go from here.
Please help, because Im not sure what to do next. Do I have to understand trigonometry, or geometry or more about triangles to solve it? I was told by my teacher there is a special relationship between the triangles PQS, PTQ and QTS. But I don't know what.
Thanks,
Jasmine (13)
Click here to see answer by solver91311(5072) |
Question 124476: 96) Ventura Capital. Henry invested $ 12,000 in a new restaurant. When the restaurant was sold two years later, he received $ 27,000. Find his average annual return by solving the equation 12,000(1 + r)^2= 27,000.T hanks
Click here to see answer by checkley71(8405) |
Question 127479: In geometry right now we are doing problems with triangles. The triangles are 30-60-90, or 45-45-90 triangles. I was just wondering if you could give me a few notes on how to do this. I am totally lost in this topic right now.
Click here to see answer by stanbon(26297) |
Question 127636This question is from textbook Geometry
: The problem is solve for x y and z. The diagram is a right triangle with the altitude drawn to the hypotenuse. The altitude divides the hypotenuse into two segements labeled x and x+1. Adjacent to x is the leg labeled x+2. Adjacent to x+1 is the leg labeled z.
I am trying to solve first for x and have tried the following, but I know it's not right:
x over x+2 = x+2 over 2x+1
x squared + 4x+4 = 2x squared +x
(subtract x squared from both sides)
4x + 4 = x squared + x
(subtract x from both sides)
3x + 4 = x squared
the square root of (3x + 4) =x
to find y and z, i need to isolate x
Thanks!This question is from textbook Geometry
Click here to see answer by stanbon(26297) |
Question 127636This question is from textbook Geometry
: The problem is solve for x y and z. The diagram is a right triangle with the altitude drawn to the hypotenuse. The altitude divides the hypotenuse into two segements labeled x and x+1. Adjacent to x is the leg labeled x+2. Adjacent to x+1 is the leg labeled z.
I am trying to solve first for x and have tried the following, but I know it's not right:
x over x+2 = x+2 over 2x+1
x squared + 4x+4 = 2x squared +x
(subtract x squared from both sides)
4x + 4 = x squared + x
(subtract x from both sides)
3x + 4 = x squared
the square root of (3x + 4) =x
to find y and z, i need to isolate x
Thanks!This question is from textbook Geometry
Click here to see answer by solver91311(5072) |
Question 128479: The hypotenuse of a right triangle is 8 ft. longer than one leg and 4 ft. longer than the other leg. What are the dimensions of this triangle? Show the equation you used to solve this and then your answer.
Click here to see answer by Earlsdon(4900) |
Question 130118: Hi! i have a question on my math homework i have to find the circumcenter of a triangle whose points are L(83,15) S(196,123) and B(22,123). i have found the midpoints which are on line: LS is (139.5,69), SB is (109,123), and LB is 52.5,69). then i found the slope of each line which is: LS 108/113, SB 0, and LB -108/61. then i have tried to find the perpendicular bisector of each but every time i do the same problem i have came out with a different number that equals b. i have tried for a few hours on this problem and i would aprieciate if you could help me find what X (of the circumcenter) would be. Thank you
Click here to see answer by stanbon(26297) |
|
Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575
|
| |
