You can
put this solution on YOUR website!a first side
a/2+4 second side
2a-7 third side
3+(3/2+4)+(2*3-7)
3+5.5+6-7
8.5-1=7.5 for the perimeter.
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Problem with this problem:
Side 3 (2*3-7)=(6-7)=-1 which is not a valid measurement for the side of a triangle.
The math works but this is a very bad problem & needs to be eliminated if it is a class problem because you can't construct or draw this triangle which is necessary in many math & geometry examples.
For this example to be valid the value of 'a' need to be > 3.5 for side 3 to have a positive length.
You can
put this solution on YOUR website!write expression for length of second side in terms of a
Given: second side is 4 more than half of a
so the expression would be

or

next
write an expression for the length of the third side in terms of a
Given: the third side is 7 less than twice a

last
find the perimeter if a = 3
Known: perimeter of a triangle equals the sum of all its sides

or
Note: this is how the math works but with the given information a=3 there is a problem. If a=3 then the third side which is 2a-7 would result in the third side being -1. There can be no triangle with this measurement.