SOLUTION: In the triangle below, side BC is 12 units long and side AC is 15 units long. If angle < C is 60 degrees, then what is side AB-squared?
A. 64
B. 81
C. 189
D. 369
E. 549
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Question 943816: In the triangle below, side BC is 12 units long and side AC is 15 units long. If angle < C is 60 degrees, then what is side AB-squared?
A. 64
B. 81
C. 189
D. 369
E. 549
I tried using the Rule of Cosines, but I'm not getting any of the answer choices.
I did: AB-squared = AC-squared + BC squared - 2(AC)(BC)cos60
(AB)^2 = (15)^2 + (12)^2 - 2(15)(12)cos60
For (AB)^2 = 711.8686
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
if units long, side units long, and angle < degrees, then we have
pay attention to the question: what is side ?
.....
=> this is
so, your answer is: C.
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