SOLUTION: If a base angle of an isoceles triangle is 16 degrees more than half of the measure of its vertex angle, than the vertex angle is ? degrees? Please show solution using equation.

Question 92988: If a base angle of an isoceles triangle is 16 degrees more than half of the measure of its vertex angle, than the vertex angle is ? degrees?
Please show solution using equation.
Thank You!
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
let x=vertex angle

the angles of a triangle (ANY TRIANGLE) sum to 180 degrees ... the 2 base angles of an isoceles triangle are equal

so, ((x/2)+16)+((x/2)+16)+x=180 ... 2x+32=180 ... 2x=148 ... x=74
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