SOLUTION: If the perimeter of a triangle is 30 and the lengths are x+3,2x and 4x-1 find the length of each side

Question 885577: If the perimeter of a triangle is 30 and the lengths are x+3,2x and 4x-1 find the length of each side

Found 2 solutions by jim_thompson5910, algebrapro18:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Perimeter of Triangle:

Perimeter = (Side1) + (Side2) + (Side3)

30 = (x+3) + (2x) + (4x-1)

30 = x+3 + 2x + 4x-1

30 = 7x+2

30-2 = 7x

28 = 7x

7x = 28

x = 28/7

x = 4

Now use this to find the length of each side

Side1: x+3 = 4+3 = 7

Side2: 2x = 2*4 = 8

Side3: 4x-1 = 4*4-1 = 15

The three sides are: 7, 8, 15

Check: 7+8+15 = 15+15 = 30

So the answer checks out.
Answer by algebrapro18(249) (Show Source): You can put this solution on YOUR website!
So to find the perimeter of a figure you need to add up all the side lengths. So we will add up x+2, 2x, and 4x-1 and set it equal to 30(the given perimeter).

x+2+2x+4x-1 = 30 moving like terms together
x+2x+4x+2-1 = 30 combining like terms
7x+1 = 30 Subtracting 1 from both sides
6x = 29 Dividing both sides by 6
x = 29/6

Now we plug x into the given expressions for the side lengths and simplify.

Side 1 = x+3 = 29/6 +3 = (29+18)/6 = 47/6
Side 2 = 2x = 2(29/6) = 29/3
Side 3 = 4x-1 = 4(29/6)-1 = 58/3 -1 = 55/3
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