SOLUTION: Solve the given equation over the interval [0.2pi) sin^2(x)-(square root of 3)sin(x)+1= cos^2(x)

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Question 864111: Solve the given equation over the interval [0.2pi) sin^2(x)-(square root of 3)sin(x)+1= cos^2(x)
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi
interval [0 - 2pi)
sin^2(x)-√3sin(x)+1= cos^2(x)
(1-cos^2(x) -√3sin(x)+1= cos^2(x)
√3sin(x)= 2(cos^2(x) - 1)
√3 sin(x)= -2sin^2(x)
-√3 /2 = sin(x)
See (c0sx, sinx) summary


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