SOLUTION: How many sides does a polygon have if the sum of the measures of its interior angles is 6 times the sum of the measures of its exterior angles
Algebra.Com
Question 85978: How many sides does a polygon have if the sum of the measures of its interior angles is 6 times the sum of the measures of its exterior angles
Answer by psychopsibilin(3) (Show Source): You can put this solution on YOUR website!
we know that for a 'n' sided polygon, the sum of interior angles is (2n-4)*90.. at the same time, we also know that the sum of exterior angles of a polygon is always 360 degrees. from the question we understand that:
(2n-4)*90 = 6*360
or 2n-4 = (6*360/9) = 24
hence 2n=28
hence n=14
Therefore the polygon has 14 sides.
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