SOLUTION: The longer leg of a right triangle is three inches more than three times the length of the shorter leg the area is 84 find the perimeter

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Question 833044: The longer leg of a right triangle is three inches more than three times the length of the shorter leg the area is 84 find the perimeter
Found 2 solutions by stanbon, MathTherapy:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
The longer leg of a right triangle is three inches more than three times the length of the shorter leg the area is 84 find the perimeter
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shorter: x
longer: 3x + 3
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Equation:
x(3x+3) = 84
3x^2 + 9x - 84 = 0
x^2 + 3x - 28 = 0
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(x+7)(x-4) = 0
Positive solution:
x = 4
3x+3 = 15
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Hypotenuse = sqrt[4^2+15^2] = sqrt[16+225] = sqrt(241)
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Perimeter = 4 + 15 + sqrt(241)
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Cheers,
Stan H.
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Answer by MathTherapy(10549)   (Show Source): You can put this solution on YOUR website!
The longer leg of a right triangle is three inches more than three times the length of the shorter leg the area is 84 find the perimeter

Shorter leg: 7 inches
Longer leg: 24 inches
Hypotenuse: 25 inches
Perimeter: inches
You can do the check!!
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