# SOLUTION: HERE AT WORK I AM TRYING TO SOLVE THIS PROBLEM AND ITS HURTIN MY HEAD! PLEASE HELP. I AM CUTTING A 15 DEGREE ANGLE ON A MACHINE. FROM THE TOP OF THE PIECE TO THE BOTTOM OF WHERE TH

Algebra ->  Algebra  -> Triangles -> SOLUTION: HERE AT WORK I AM TRYING TO SOLVE THIS PROBLEM AND ITS HURTIN MY HEAD! PLEASE HELP. I AM CUTTING A 15 DEGREE ANGLE ON A MACHINE. FROM THE TOP OF THE PIECE TO THE BOTTOM OF WHERE TH      Log On

 Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Geometry: Triangles Solvers Lessons Answers archive Quiz In Depth

 Question 82481: HERE AT WORK I AM TRYING TO SOLVE THIS PROBLEM AND ITS HURTIN MY HEAD! PLEASE HELP. I AM CUTTING A 15 DEGREE ANGLE ON A MACHINE. FROM THE TOP OF THE PIECE TO THE BOTTOM OF WHERE THE DEGREE MUST END IS 1.75 INCHES. I CAN'T SEEM TO FIGURE OUT HOW FAR IN THE SHORT SIDE IS.Answer by stanbon(57203)   (Show Source): You can put this solution on YOUR website!I AM CUTTING A 15 DEGREE ANGLE ON A MACHINE. FROM THE TOP OF THE PIECE TO THE BOTTOM OF WHERE THE DEGREE MUST END IS 1.75 INCHES. I CAN'T SEEM TO FIGURE OUT HOW FAR IN THE SHORT SIDE IS. ------------ If I read you right you have a right triangle; the angle at the top is 15 degrees; the side perpendicular to the base is 1.75 inches; the length of the side opposite the 90 degree angle is of no interest to you; you want to know the length of the 3rd side which is the shortest side of the triangle. -------- Let the length of that side be "x" Then tan(15)=x/1.75 x=1.75*tan(15) x=0.4689 inches ============== Cheers, Stan H.